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5a^2-31a+30=0
a = 5; b = -31; c = +30;
Δ = b2-4ac
Δ = -312-4·5·30
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-19}{2*5}=\frac{12}{10} =1+1/5 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+19}{2*5}=\frac{50}{10} =5 $
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